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x^2+10x+24=2x+4
We move all terms to the left:
x^2+10x+24-(2x+4)=0
We get rid of parentheses
x^2+10x-2x-4+24=0
We add all the numbers together, and all the variables
x^2+8x+20=0
a = 1; b = 8; c = +20;
Δ = b2-4ac
Δ = 82-4·1·20
Δ = -16
Delta is less than zero, so there is no solution for the equation
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